Char cannot be dereferenced equalsignorecase

We have seen earlier comparing two Character objects with equals method. It was case sensitive comparison. Infact, Character class does not have a method like equalsIgnoreCase.

But String has one. Apply a small technique to do case insensitive comparison with characters. Just convert both the characters in comparison either to uppercase or lowercase. For this use toUppertCase or toLowerCase methods and then compare. Output screenshot of Use equalsIgnoreCase with Character objects.

Pass your comments and suggestions to improve the quality of this tutorial "Use equalsIgnoreCase with Character objects". Here equals method of String class is used to compare two characters.

Or you can use equalsIgnoreCase method for case-insensitive comparison. The above program is a mater of interest and not used practically as equals you can use directly with character objects. See equals example in the same series. Your email address will not be published.

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Notify me of new posts by email. Leave a Reply Cancel reply Your email address will not be published.So i'm new to this and during my challenge i keep getting this error message but i can't figure out how to fix it, or rather what i'm doing wrong i suppose.

I thought i did it right, can anyone explain to me what i'm doing wrong? Thank you! The trouble that is getting caused is because you're trying to set up your boolean, I think that java thinks you're trying to change the value to be the string representation of true, instead of a boolean.

In reality you have all the code that you need to pass this challenge minus a few adjustments good job. The first thing to do is take out the boolean.

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Also, be sure to name your string as response, otherwise the challenge won't allow you to move on to the next step, so it should look something like, and when we're checking to see if we want to break out of the loop, check to see if the response is equal to no. Other than that, good job again! Ooohhh okay, the course just prior to the quiz was talking about booleans in the end, so when the question talked about storing the answer i assumed thats what it was asking me to do, lol.

Hey Rian, no worries, this was actually a really well done, it looks like you trying to overcomplicate it a bit.

char cannot be dereferenced equalsignorecase

Happens to the best of us. The while part of it is always a little sketchy at first, but think of it this way, in a do while loop, as long as that condition is met, the code will continue to execute. I'm a little unsure how to do this exactly, so do i create a new variable called answer or something and put it just below the "do" "while" section?

I get this dereferenced error when I try to compile my java code?

So what the question is wanting is for you to print a formatted string and pass the variable in directly. What we're doing here is about the same, except that we're telling java to pass in firstName as the first value, and blue for the second, as it will always follow a linear path.

So this program is expecting you to write. Gaawwwwdddd are you serious?! I remember doing that in like the second course! I think what i'll do is just go back and watch all of the videos up til this point to refresh my memory and help drill it all into my head. Thanks again for all your help man, you're a savior :. It's okay, I'm terrible at overthinking things too! Good luck with everything, don't hesitate to reach back out to the forums or me if you have any more questions.

Posting to the forum is only allowed for members with active accounts. Please sign in or sign up to post. I forgot my password. Ryan Loveland Points. Console for you. It is in a variable named console. Rob Bridges 14, Points.

Rob Bridges Rob Bridges 14, Points. Hey there Rian, The trouble that is getting caused is because you're trying to set up your boolean, I think that java thinks you're trying to change the value to be the string representation of true, instead of a boolean. Ryan Loveland Ryan Loveland Points. Thanks, I hope that helps.Any intelligent fool can make things bigger, more complex, and more violent. It takes a touch of genius - and a lot of courage - to move in the opposite direction.

Forum: Beginning Java. Jem Edwards. The last piece of my puzzle - I don't understand how to use the equalsIgnoreCase method. In my program I ask the user to input a 'c' or 'f' for celcius or farenheit. I want my program to ignore the case and accept either upper or lowercase. I have searched the internet for the past two days and every site I found including Java Sun Tutorial and Java Ranch doesn't break it down clearly to me.

Haven't heard a peep from my homework board since I posted early this morning so I'm back here for help. David Weitzman. Your declaration of fahrenheitCelsius probably looks something like this: char fahrenheitCelsius; Note that fahrenheitCelsius is not a java.

String -- it's a char. Michael Morris. Hi Jem, Apparently your variable fahrenheitCelsius is declared as a char. Since a char is a primative, the compiler is telling you that it cannot be dereferened. The equalsIgnoreCase is a member of the String class. So, if you want to use that method you'll need a String. Thank you David and Michael. You were both exactly right about the declaration of fahrenheitCelsius.

I tried both solutions and both gave me a couple of compiling errors. So after working on errors for both programs I was able to get the program with David's solution to compile however now I can't get it to give me an output.

Previously I was able to get the program to do the conversions as long as I entered an uppercase C or F but now when I enter any case it gives me the System. I've narrowed down my errors using Michael's solution and I'll try to fix those also so I can compile and see if it runs. I figure still trying to fix the errors will help me learn more about Java.

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Would someone please give me an opinion on why my program no longer gives me the answer? Thank you! I was expecting that you might come across this. But it's good for you to know anyway. You're not using equalsIgnoreCase.Our members have a wide range of skills and they all have one thing in common: A passion to learn and code Java.

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Thread: Char cannot be dereferenced!!

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Char cannot be dereferenced!! Hi all im working on a program and have got the error "char cannot be dereferenced". The for loop iterates through the array "people" and sends a message to each one using the method "getPerson ".

This method gets a single character from a StringBuilder array. The method is declared as the return type char so i used. I am a novice in java so im not even sure im going about this theright way! I hope someone can help because I just cant see a way forward!

char cannot be dereferenced equalsignorecase

Thankyou in advance for anyone willing to help. Last edited by helloworld; February 13th, at PM. Related threads: Char cannot be dereferenced Check Password Program Rock Paper Scissors issue decimal to hexadecimal 2d 4x4 array insdie a 1d array. Block cipher how can i convert unicode to string? Help with Java code, java parser my encrypting simple client to server program unable to get the key from client missing return statement need help!! Re: Char cannot be dereferenced!!

Please help Strings should be compared using the. Please help I had already tried that before I posted but when I tried to compile it just kept telling me I needed a bracket on the line shown below and if I added a bracket it just continued giving that error:.

char cannot be dereferenced equalsignorecase

Last edited by helloworld; February 15th, at PM. Please help it should be:. Please help Hi thankyou for the advice, I have changed the code so its a you say but I get the same char cannot be dereferenced error when i try to compile. Similar Threads char toUppercase? Need help with concatenizing char? All times are GMT The time now is AM.But abc is a const string Its stored in initialized data segment.

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The pointer is to be known by the name "p," and can point to any char or contiguous array of chars anywhere. Hence in this declaration, a can be made to point to a different string whereas in the first declaration,a cannot be assigned to another string directly. It can be done only through strcpy CareerCup's interview videos give you a real-life look at technical interviews.

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Learn More.By using our site, you acknowledge that you have read and understand our Cookie PolicyPrivacy Policyand our Terms of Service. The dark mode beta is finally here. Change your preferences any time. Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share information. What I want is no matter what the user inputs, if the first letter of their input is either a 'y' or 'n' regardless of case, it will print "game start".

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I've tried equalsIgnoreCase with the "letter" variable but it gives the error: char cannot be dereferenced. Any recommendations will be really appreciated on this!

For your case, if you want to use that method, you can do this:. Learn more. Java - charAtequalsIgnoreCase, if statement testing? Ask Question. Asked 5 years, 2 months ago. Active 5 years, 2 months ago. Viewed 4k times. Krease ClaytonR ClaytonR 43 1 1 silver badge 5 5 bronze badges. Is that supposed to be a 'p' or a 'n'? Your code checks for y and p. Active Oldest Votes.

Try use Character toLowercase : if Character. M Anouti M Anouti You could pre-build a set of acceptable characters. OldCurmudgeon OldCurmudgeon 58k 15 15 gold badges 98 98 silver badges bronze badges.

Holger - Working on that If you want to test against a pre-built a set of acceptable characters, you may consider "yYnN". For such a small set, hashing is not faster than a linear search. Holger - I was thinking of using a custom comparator too - but decided that was a little too OTT.

Good point on the indexOf. Sign up or log in Sign up using Google. Sign up using Facebook. Sign up using Email and Password. Post as a guest Name.

Email Required, but never shown. The Overflow Blog. Featured on Meta.Java has two different types of variables: primitive and objects and only objects are reference types. The type int is a primitive and not an object.

Dereferencing is the process of accessing the value referred to by a reference. Since, int is already a value not a referenceit can not be dereferenced.

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Primitives byte, char, short, int, long, float, double, boolean are not objects and do not have member variables or methods. They're just simple values. So you cannot do somePrimitive. So in the above example, x is an int, a primitive, and therefore cannot be dereferenced - meaning x.

This means that there are primitive typesoriginally designed for speed, that do not behave as objects. The primitive types exist either as local variables on the stack, or as fields static or not of objects. In Java, objects are always allocated on the heap : if you have a local variable that seems an object, then the object itself is allocated on the heap and the stack contains only a reference, i.

Important to note that NOT to stack memory. As a result of this fact, you cannot dereference a primitive type because you cannot create a reference to something different than an object, primitive types are not objects.

So, we can say that accessing the state or behaviour of an object using its reference with the help of the dot. Home C VB. Int cannot be dereferenced: Java Java has two different types of variables: primitive and objects and only objects are reference types. Java Dereferencing Java has two different types of variables: primitive and objects and only objects are reference types.

Reached end of file while parsing Unreachable statement error in Java How to fix java. SocketException: Connection reset. All other trademarks are property of their respective owners.


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